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Worker pools

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Worker pools are a model in which a fixed number of m workers (implemented in Go with goroutines) work their way through n tasks in a work queue (implemented in Go with a channel). Work stays in a queue until a worker finishes up its current task and pulls a new one off.

Basically there are a set amount of workers and n tasks. Every worker takes a task, and when it’s done it takes another one. This is very useful for breakable task that require a lot of processing.

This is an example program:

package main

import "fmt"

func Worker(id int, jobs <- chan int, results chan <- int) {
	for job := range jobs {
		fmt.Printf("--> Worker #%d started fib with %d\n", id, job)
		fib := Fibo(job)
		fmt.Printf("Worker #%d finished. Job: %d; Fibo: %d\n", id, job, fib)
		results <- fib
	}
}

func Fibo(n int) int {
	if n <= 1 {
		return n
	}

	return Fibo(n - 1) + Fibo(n - 2)
}

func main() {
	tasks := []int{2, 3, 4, 7, 10, 15}
	nWorkers := 3
	jobs := make(chan int, len(tasks))
	results := make(chan int, len(tasks))

	// creates the workers
	for i := 0; i < nWorkers; i++ {
		go Worker(i, jobs, results)
	}

	// sends them to work
	for _, v := range tasks {
		jobs <- v
	}

	// close channel to indicate that's all the work to do
	close(jobs)

	for i := 0; i < len(tasks); i++ {
		<- results
	}
}

Explanation

https://gobyexample.com/worker-pools

Escribí unas modificaciones del código visto en clase para observar realmente cómo es que las gorutines y los workers funcionan a gran escala (o bueno eso creo), el código al final de su ejecución dice cuánto tiempo tomó y en mi caso, realizando las series de Fibonacci con los workers y gorutines tomó 9.544643109 segundos, de la forma convencional tomó 18.054724068 les dejo el código por si alguien quiere probarlo, sólo deben cambiar el valor de la constante withGoRutinesAndWorkers para hacer la ejecución de una forma u otra.

Código:

package main

import (
	"fmt"
	"time"
)

func Worker(id int, jobs <-chan int, results chan<- int) {
	for job := range jobs {
		fmt.Printf("Worker with id %d started fib with %d\n", id, job)
		fib := Fibonacci(job)
		fmt.Printf("Worker with id %d has finished the job %d, and fib %d\n", id, job, fib)
		results <- fib
	}
}

func Fibonacci(n int) int {
	if n <= 1 {
		return n
	}
	return Fibonacci(n-1) + Fibonacci(n-2)
}

func main() {
	start := time.Now()
	tasks := []int{2, 34, 36, 17, 10, 40, 6, 22, 41, 44, 33, 2, 5, 2, 34, 36, 17, 10, 40, 6, 22, 41, 44, 33, 2, 5, 17, 10, 40, 6, 22, 2, 5, 2, 34, 36, 22, 41, 44}
	const withGoRutinesAndWorkers = false
	if withGoRutinesAndWorkers {
		nWorkers := 12
		jobs := make(chan int, len(tasks))
		results := make(chan int, len(tasks))

		for i := 0; i <= nWorkers; i++ {
			go Worker(i, jobs, results)
		}

		for _, value := range tasks {
			jobs <- value
		}
		close(jobs)

		for i := 0; i < len(tasks); i++ {
			<-results
		}
	} else {

		for _, v := range tasks {
			val := Fibonacci(v)
			fmt.Println("val->", val)
		}

	}

	elapsed := time.Since(start)
	fmt.Printf("Program took %s", elapsed)

}

Si alguien no entiende puede tratar con este codigo, tienes unos prints y unos sleep para comprender mejor lo q pasa paso a paso

package main

import (
	"fmt"
	"time"
)

func Worker(id int, jobs <-chan int, results chan<- int) {
	fmt.Println("Worker with id", id, "started")
	for j := range jobs {
		fmt.Printf("Worker with id %v started job %v\n", id, j)
		results <- Fibonacci(j)
		fmt.Printf("Worker with id %v finished job %v\n", id, j)
	}
}

func Fibonacci(n int) int {
	if n <= 1 {
		return n
	}
	return Fibonacci(n-1) + Fibonacci(n-2)
}

func main() {
	tasks := []int{7, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42}
	jobs := make(chan int, len(tasks))
	results := make(chan int, len(tasks))
	for w := 1; w <= 3; w++ {
		go Worker(w, jobs, results)
	}
	time.Sleep(3 * time.Second)
	for _, task := range tasks {
		println("Sending task", task)
		jobs <- task
		time.Sleep(1 * time.Second)
	}
	close(jobs)
	for a := 1; a <= len(tasks); a++ {
		fmt.Println(<-results)
	}
}

Basicamente un worker es la combinación de Buffered Channels, GoRoutines y se emplea el patrón de semáforos.

Es interesante saber como funciona la función recursiva para resolver el fibonacci, dejo link donde lo explican:
Fibonacci

package main

import "fmt"

// Worker is a function that does the work.
func Worker(id int, jobs <-chan int, results chan<- int) {
	for j := range jobs {
		fmt.Println("worker", id, "started  job", j)
		fib := Fibonnaci(j)
		results <- fib
		fmt.Println("worker", id, "finished job", j, "result", fib)
	}
}

// Fibonacci returns the nth number in the Fibonacci sequence.
func Fibonnaci(n int) int {
	if n < 2 {
		return n
	}
	return Fibonnaci(n-1) + Fibonnaci(n-2)
}

func main() {
	// tasks to do
	tasks := []int{2, 3, 4, 5, 7, 10, 12, 35, 37, 40, 41, 42}

	nWorkers := 5
	jobs := make(chan int, len(tasks))
	results := make(chan int, len(tasks))

	// start the workers
	for w := 1; w <= nWorkers; w++ {
		go Worker(w, jobs, results)
	}

	// give the workers jobs
	for _, t := range tasks {
		jobs <- t
	}
	close(jobs)

	// get the results (consume the channel)
	for a := 1; a <= len(tasks); a++ {
		<-results
	}
}

por que no se pasa como referencia usando '&' ?

Les dejo un ejemplo de este ejercicio usando WaitGroups, en lugar de un channel extra (results). El canal results no me parecio necesario asi que decidi borrarlo y tiene el mismo funcionamiento.

package main

import (
	"fmt"
	"sync"
)

var (
	wg = sync.WaitGroup{}
)

func Worker(id int, jobs <-chan int) {
	for job := range jobs {
		fmt.Printf("Worker with id %d started fib with %d\n", id, job)
		fib := Fibonacci(job)
		fmt.Printf("Worker with id %d, job %d fib with %d\n", id, job, fib)
		wg.Done()
	}
}

func Fibonacci(n int) int {
	if n <= 1 {
		return n
	}
	return Fibonacci(n-1) + Fibonacci(n-2)
}

func main() {
	tasks := []int{2, 3, 4, 5, 7, 10, 12, 40}
	nWorkers := 3
	jobs := make(chan int, len(tasks))

	for i := 0; i < nWorkers; i++ {
		go Worker(i, jobs)
	}

	for _, value := range tasks {
		wg.Add(1)
		jobs <- value
	}
	close(jobs)

	wg.Wait()
}

Estaba viendo ¿Por qué en los resultados sólo hay dos IDs? Y resulta que es por que en la condición del “for” puso “i<3” por lo que solo se crearon 2 workers y no 3