Playground: Search 2D Array Matrix

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Playground: Search 2D Array Matrix

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Ángel Vargas Casavantes

student

Comparto mi intento en JS :]

function searchInMatrix(matrix, target) {
	let up = 0, left = 0;
	let down = matrix.length - 1, right = matrix[up].length - 1;
	let half, selectedRow;

	while (up <= down) { // Busqueda por columna
		half = Math.floor(up + (down - up) / 2);
		
		if (up == down) {
			selectedRow = up;
			break;
		}

		if (matrix[up][right] <= target && matrix[half][right] < target) 
			up = half+1;
		else
			down = half;
	}

	while (left <= right) { // Busqueda por fila
		half = Math.floor(left + (right - left) / 2);

		if (matrix[selectedRow][half] < target)
			left = half + 1; //: Descartamos mitad izq.
		else
			right = half - 1; //: Descartamos mitad der.

		if (matrix[selectedRow][half] == target)
			return true
	}

	return false;
}

John Eduard Meneses González

student

Share my solution!!

Carlos Hernandez

student

Mi solución en JS:const search2DArrayMatrix = (matrix, target) => { const rows = matrix.length; let rowsTop = 0; let rowsBottom = rows - 1; while (rowsTop <= rowsBottom) { const rowsHalf = Math.floor((rowsBottom + rowsTop) / 2); const currentRow = matrix[rowsHalf]; const currentRowLength = matrix[rowsHalf].length; // Find row if (currentRow[0] <= target && currentRow[currentRowLength - 1] >= target) { console.log('Found row that contains range'); let left = 0; let right = currentRowLength - 1; while (left <= right) { const half = Math.floor((right + left) / 2);

if (currentRow[half] === target) { console.log(Found at position: (${rowsHalf}, ${half})); return true; } if (target > currentRow[half]) { left = half + 1; } if (target < currentRow[half]) { right = half - 1; } } break; } if (target > currentRow[currentRowLength - 1]) { rowsTop = rowsHalf + 1; } if (target < currentRow[0]) { rowsBottom = rowsHalf - 1; } } return false;} const DATA_INPUT_1 = [ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 60],]; console.log(search2DArrayMatrix(DATA_INPUT_1, 16));console.log(search2DArrayMatrix(DATA_INPUT_1, 60));console.log(search2DArrayMatrix(DATA_INPUT_1, 2));

const search2DArrayMatrix = (matrix, target) => {
    const rows = matrix.length;

    let rowsTop = 0;
    let rowsBottom = rows - 1;

    while (rowsTop <= rowsBottom) {
        const rowsHalf = Math.floor((rowsBottom + rowsTop) / 2);

        const currentRow = matrix[rowsHalf];
        const currentRowLength = matrix[rowsHalf].length;

        // Find row
        if (currentRow[0] <= target && currentRow[currentRowLength - 1] >= target) {
            console.log('Found row that contains range');
            let left = 0;
            let right = currentRowLength - 1;

            while (left <= right) {
                const half = Math.floor((right + left) / 2);


                if (currentRow[half] === target) {
                    console.log(`Found at position: (${rowsHalf}, ${half})`);
                    return true;
                }

                if (target > currentRow[half]) {
                    left = half + 1;
                }

                if (target < currentRow[half]) {
                    right = half - 1;
                }
            }
            break;
        }
        if (target > currentRow[currentRowLength - 1]) {
            rowsTop = rowsHalf + 1;
        }
        if (target < currentRow[0]) {
            rowsBottom = rowsHalf - 1;
        }
    }

    return false;
}

const DATA_INPUT_1 = [
    [1, 3, 5, 7],
    [10, 11, 16, 20],
    [23, 30, 34, 60],
];

console.log(search2DArrayMatrix(DATA_INPUT_1, 16));
console.log(search2DArrayMatrix(DATA_INPUT_1, 60));
console.log(search2DArrayMatrix(DATA_INPUT_1, 2));

Bryan Castano

student

Hello Guys, This is my Code, I took willing from some of you in the Past on your comments here bellow \n

# Search 2D Array Matrix  .....

from typing import List

def searchInMatrix(matrix: List[List[int]], Target  : int ) -> bool:

  m  = len(matrix)
  n  = len(matrix[0])
    
  left  = 0 
  right = m * n - 1
    
  while ( left <= right ) :
    
    mid = left + ( right - left ) // 2
        
    row_mid = mid // n
        
    column_mid = mid % n
        
    if  ( Target == matrix[row_mid][column_mid] )  :
        
      return True
            
    if ( Target < matrix[row_mid][column_mid]  )  : 
        
      right = mid - 1
            
    else:
        
      left  = mid + 1

  return False
  
  

matrix = [
  [1,3,5,7],
  [10,11,16,20],
  [23,30,34,60],
]

print(matrix)

response = searchInMatrix(matrix, 3)

print(response)

response2 = searchInMatrix(matrix,  12)

print(response2)

```# Search 2D Array Matrix  .....



from typing import List



def searchInMatrix(matrix: List\[List\[int]], Target  : int ) -> bool:



&#x20; m  = len(matrix)

&#x20; n  = len(matrix\[0])

&#x20;  &#x20;

&#x20; left  = 0&#x20;

&#x20; right = m \* n - 1

&#x20;  &#x20;

&#x20; while ( left <= right ) :

&#x20;  &#x20;

&#x20;   mid = left + ( right - left ) // 2

&#x20;      &#x20;

&#x20;   row\_mid = mid // n

&#x20;      &#x20;

&#x20;   column\_mid = mid % n

&#x20;      &#x20;

&#x20;   if  ( Target == matrix\[row\_mid]\[column\_mid] )  :

&#x20;      &#x20;

&#x20;     return True

&#x20;          &#x20;

&#x20;   if ( Target < matrix\[row\_mid]\[column\_mid]  )  :&#x20;

&#x20;      &#x20;

&#x20;     right = mid - 1

&#x20;          &#x20;

&#x20;   else:

&#x20;      &#x20;

&#x20;     left  = mid + 1



&#x20; return False

&#x20;&#x20;

&#x20;&#x20;



matrix = \[

&#x20; \[1,3,5,7],

&#x20; \[10,11,16,20],

&#x20; \[23,30,34,60],

]



print(matrix)



response = searchInMatrix(matrix, 3)



print(response)



response2 = searchInMatrix(matrix,  12)



print(response2)

Carlos Damián Loaiza Artunduaga

student

Vuelvo a dejar mi solución funcional aquí:

def searchMatrix(matrix: list[list[int]], target: int) -> bool:
    n = len(matrix[0])
    i, d = 0, len(matrix) * n - 1
    while i <= d:
        mi = i + (d - i) // 2
        fmi = mi // n
        cmi = mi % n
        if target == matrix[fmi][cmi]:
            return True
        if target < matrix[fmi][cmi]:
            d = mi - 1
        else:
            i = mi + 1
    return False

Miguel Angel Reyes Moreno

student

Comparto mi solución:

from typing import List
def searchInMatrix(matriz: List\[List\[int]], objetivo: int) -> bool:  m = len(matriz)  n = len(matriz\[0])  left = 0  right = (m\*n) - 1
&#x20; while left <= right:      k = (left + right) // 2      row = k // n      col = k % n      if matriz\[row]\[col] == objetivo:          return True #\* target is found      elif matriz\[row]\[col] < objetivo:          left = k + 1      else:          right = k - 1
&#x20; return False #\* target is not found

Nicolas Alpargatero

student

Vengo aprender a traves de un Playground la declaración de tipo de variables, super útil, porque yo creaba variable auxiliar para darle dir() y help() jajaj

. . .

function searchInMatrix(matrix, target) {
	let up = 0, left = 0;
	let down = matrix.length - 1, right = matrix[up].length - 1;
	let half, selectedRow;

	while (up <= down) { // Busqueda por columna
		half = Math.floor(up + (down - up) / 2);
		
		if (up == down) {
			selectedRow = up;
			break;
		}

		if (matrix[up][right] <= target && matrix[half][right] < target) 
			up = half+1;
		else
			down = half;
	}

	while (left <= right) { // Busqueda por fila
		half = Math.floor(left + (right - left) / 2);

		if (matrix[selectedRow][half] < target)
			left = half + 1; //: Descartamos mitad izq.
		else
			right = half - 1; //: Descartamos mitad der.

		if (matrix[selectedRow][half] == target)
			return true
	}

	return false;
}

const search2DArrayMatrix = (matrix, target) => {
    const rows = matrix.length;

    let rowsTop = 0;
    let rowsBottom = rows - 1;

    while (rowsTop <= rowsBottom) {
        const rowsHalf = Math.floor((rowsBottom + rowsTop) / 2);

        const currentRow = matrix[rowsHalf];
        const currentRowLength = matrix[rowsHalf].length;

        // Find row
        if (currentRow[0] <= target && currentRow[currentRowLength - 1] >= target) {
            console.log('Found row that contains range');
            let left = 0;
            let right = currentRowLength - 1;

            while (left <= right) {
                const half = Math.floor((right + left) / 2);


                if (currentRow[half] === target) {
                    console.log(`Found at position: (${rowsHalf}, ${half})`);
                    return true;
                }

                if (target > currentRow[half]) {
                    left = half + 1;
                }

                if (target < currentRow[half]) {
                    right = half - 1;
                }
            }
            break;
        }
        if (target > currentRow[currentRowLength - 1]) {
            rowsTop = rowsHalf + 1;
        }
        if (target < currentRow[0]) {
            rowsBottom = rowsHalf - 1;
        }
    }

    return false;
}

const DATA_INPUT_1 = [
    [1, 3, 5, 7],
    [10, 11, 16, 20],
    [23, 30, 34, 60],
];

console.log(search2DArrayMatrix(DATA_INPUT_1, 16));
console.log(search2DArrayMatrix(DATA_INPUT_1, 60));
console.log(search2DArrayMatrix(DATA_INPUT_1, 2));

# Search 2D Array Matrix  .....

from typing import List

def searchInMatrix(matrix: List[List[int]], Target  : int ) -> bool:

  m  = len(matrix)
  n  = len(matrix[0])
    
  left  = 0 
  right = m * n - 1
    
  while ( left <= right ) :
    
    mid = left + ( right - left ) // 2
        
    row_mid = mid // n
        
    column_mid = mid % n
        
    if  ( Target == matrix[row_mid][column_mid] )  :
        
      return True
            
    if ( Target < matrix[row_mid][column_mid]  )  : 
        
      right = mid - 1
            
    else:
        
      left  = mid + 1

  return False
  
matrix = [
  [1,3,5,7],
  [10,11,16,20],
  [23,30,34,60],
]

print(matrix)

response = searchInMatrix(matrix, 3)

print(response)

response2 = searchInMatrix(matrix,  12)

print(response2)

```# Search 2D Array Matrix  .....

from typing import List

def searchInMatrix(matrix: List\[List\[int]], Target  : int ) -> bool:

&#x20; m  = len(matrix)

&#x20; n  = len(matrix\[0])

&#x20;  &#x20;

&#x20; left  = 0&#x20;

&#x20; right = m \* n - 1

&#x20;  &#x20;

&#x20; while ( left <= right ) :

&#x20;  &#x20;

&#x20;   mid = left + ( right - left ) // 2

&#x20;      &#x20;

&#x20;   row\_mid = mid // n

&#x20;      &#x20;

&#x20;   column\_mid = mid % n

&#x20;      &#x20;

&#x20;   if  ( Target == matrix\[row\_mid]\[column\_mid] )  :

&#x20;      &#x20;

&#x20;     return True

&#x20;          &#x20;

&#x20;   if ( Target < matrix\[row\_mid]\[column\_mid]  )  :&#x20;

&#x20;      &#x20;

&#x20;     right = mid - 1

&#x20;          &#x20;

&#x20;   else:

&#x20;      &#x20;

&#x20;     left  = mid + 1

&#x20; return False

&#x20;&#x20;

&#x20;&#x20;

matrix = \[

&#x20; \[1,3,5,7],

&#x20; \[10,11,16,20],

&#x20; \[23,30,34,60],

]

print(matrix)

response = searchInMatrix(matrix, 3)

print(response)

response2 = searchInMatrix(matrix,  12)

print(response2)

def searchMatrix(matrix: list[list[int]], target: int) -> bool:
    n = len(matrix[0])
    i, d = 0, len(matrix) * n - 1
    while i <= d:
        mi = i + (d - i) // 2
        fmi = mi // n
        cmi = mi % n
        if target == matrix[fmi][cmi]:
            return True
        if target < matrix[fmi][cmi]:
            d = mi - 1
        else:
            i = mi + 1
    return False

from typing import List
def searchInMatrix(matriz: List\[List\[int]], objetivo: int) -> bool:  m = len(matriz)  n = len(matriz\[0])  left = 0  right = (m\*n) - 1
&#x20; while left <= right:      k = (left + right) // 2      row = k // n      col = k % n      if matriz\[row]\[col] == objetivo:          return True #\* target is found      elif matriz\[row]\[col] < objetivo:          left = k + 1      else:          right = k - 1
&#x20; return False #\* target is not found

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Estructuras de Datos Lineales: Conceptos y Aplicaciones