Calcula la longitud de las palabras

Nicolas Alpargatero

student•

Hay que escoger entre las dos declaraciones del Zen de python Flat is better than nested. o Explicit is better than implicit. solo por reto escogí plano es mejor que anidando 🐍 porque entre mas larga sea la línea más complicada de captar rápido.

. .

Maga Hernandez

student•

wow!!

Eduardo Monzón

student•

Lo que me gusta de esta solución es que usa el hecho de que no se puede tener la misma llave más de una vez en el diccionario; por ello no es necesario agregar ninguna condición para las palabras que tienen la misma cantidad de letras.

Jhon Sebastián Monsalve Gomez

student•

Aqui mi solucion: . . . . . . . . .

def count_words_by_length(words):
  # Tu código aquí 👈
  list_word = [len(word) for word in words]
  return {word: list_word.count(word) for word in list_word}

Harold Zurita Simon

student•

Solución… Esto es muy divertido 😄 .

. . . .

def count_words_by_length(words):
  return {
    len(word): len([
        item 
        for item in words 
        if len(item) == len(word)
        ]) 
        for word in words
    }

Edgar Alarcón

student•

Waldir Zapata Garcia

student•

solución:

def count_words_by_length(words):
    return {len(propword): len([countfruit for countfruit in words if len(propword) == len(countfruit) ]) for propword in words  }

if __name__ == '__main__':
  list01 = [
    "apple",
    "banana",
    "orange",
    "grapefruit",
    "pear",
    "kiwi"
  ]
  response = count_words_by_length(list01)
  print(response)

  list02 = [
    "apple",
    "banana",
    "orange"
  ]
  response = count_words_by_length(list02)
  print(response)

Johan Espejo

student•

hola esta fue mi solución:

. . . . . . . . . . . def count_words_by_length(words): result= {len(palabra):len(list(filter(lambda vol:vol if len(palabra) == len(vol) else 0,words))) for palabra in words} return result

Diego Martínez Maqueda

student•

Les comparto mi solución empleando list comprehension y dictionary comprehension

def count_words_by_length(words):
  # Tu código aquí 👈
  words_by_length = {
    len(word): [
      len(word) for word in words
    ].count(len(word)) for word in words
  }
  return words_by_length
  pass

Emmanuel Paiva

student•

Mi solución:

def count_words_by_length(words):
  # Tu código aquí 👈
  counter =  [len(word) for word in words]
  return {num: counter.count(num)  for num in counter }

Francisco Pin

student•

def count_words_by_length(words):
  # Tu código aquí 👈
  l1 = ([len(word) for word in words])
  return {fruta : l1.count(fruta) for fruta in l1}
  pass
```def count\_words\_by\_length(words):  # Tu código aquí 👈  l1 = (\[len(word) for word in words])  return {fruta : l1.count(fruta) for fruta in l1}  pass

Manuel Gomez

student•

otra forma, esta si me funciono en el play ground

def count_words_by_length(words): return { len(word) : [len(word) for word in words].count(len(word)) for word in words}

print(count_words_by_length(words))

Dender Adrian Pernia Valero

student•

Marcos Bonifasi

student•

Hola, I just want to share how I coded it

Enrique Barrera

student•

tratando de adaptarme a los tiempos modernos:

def count_words_by_length(words):
  
  return {longitud: sum(1 for palabra in words if len(palabra) == longitud) for longitud in set(map(len, words))}

Victor Javier Vidal Durón

student•

def count_words_by_length(words):
    return { len(word) : sum(1 for w in words if len(w) == len(word)) for word in words }

Braulio Rangel

student•

def count_words_by_length(words):
  out = {}
  for word in words:
    if out.get(len(word)):
      out[len(word)] += 1
    else:
      out[len(word)] = 1

  print(out)
  return out

Alejandro Anaya

student•

🛡️🛡️Escudo anti-spoilers🛡️🛡️

Mi solución al reto:

def count_words_by_length(words):
  return { 
    len(w): sum(
    1 for i in words 
      if len(i) == len(w))
    for w in words 
  }

Didier Fernando Aragón Moreno

student•

def count_words_by_length(words):
  # Tu código aquí 👈
  result = {}
  for word in words:
    letters = 0
    for letter in word:
      letters += 1
    if letters in result:
      result[letters] += 1
    else:
      result[letters] = 1
  return result
  
words = count_words_by_length(["apple", "ana", "rio"])
print(words)

José Miguel Reyes

student•

. . . . . . . . . .

Mi código:

def count_words_by_length(words):
  count_words = [len(word) for word in words]
  return {word: count_words.count(word) for word in count_words}

Waldir Zapata Garcia

student•

Luis Kennedy Saavedra Fuentes

student•

Sin diccionario comprehension:

def count_words_by_length(words):
  """Function to count words by length"""
  # Declaro a Dict
  words_by_length = {}

  if not words:
    return words_by_length
    
  # Itero the words list for create the dict with dict comprehension
  for word in words:
    # Calculate len of the word
    len_word = len(word)
    if len_word not in words_by_length:
      words_by_length[len_word] = 1
    else:
      words_by_length[len_word] += 1
  return words_by_length

  # Dictionary comprehension
  # return [words_by_length[len(word)] = 1 if len(word) not in words_by_length else words_by_length[len(word)]+=1 for word in words]


if __name__ == '__main__':
  words = ["apple", "banana", "orange", "grapefruit", "pear", "kiwi"]
  words2 = []

  response = count_words_by_length(words2)
  print(response)